Selasa, 04 Desember 2012
Rabu, 03 Oktober 2012
Selasa, 02 Oktober 2012
Tugas aljabar Linear
1. 2x + 5y = 2
4x + y
= 3
Di eliminasikan
8x + 20y = 8
8y
= 2
Y
= 2 =
1
2x + 5y = 2
2x + 5(1/4) = 2
2x + 5/4 = 2
2x = 2 -5/4
X = 2 -5/4
Titik potong = (2 -5/4 , -1 )
2.
Titik A ( -3,5 ) dengan M = 4
Jawab :
Y = mx + b
Y –y1 = m (x – x1)
Y – (5) =
4 (x – (-3) )
Y -
5 = 4 ( x
+ 3)
Y – 5 = 4x + 12
Y = 4x + 12 + 5
Y = 4x + 17
3.Titik A ( -2,5) ,Tititk B (3, -11) Dengan M = 2
Y – y1
= x-x1
y-5 =
x-(-2)
y-5 =
x+2
y-5 = x+2
5(y-5)
= -16(x+2)
5y
= -16x-32+25
5y
= -16x-7
Y
= -16x-7
Langganan:
Postingan (Atom)




















